Question

The quadratic equation 8 sec²q – 6secq + 1 = 0 has –

• A. Exactly two roots
• B. Exactly four roots
• C. Infinitely many roots
• D. No roots

Answer 1

Answer: (D)

No roots

Answer 2

secq = $\frac{6 \pm \sqrt{36 - 32}}{16}$ = $\frac{6 \pm 2}{16}$

secq = $\frac{1}{2}$ or $\frac{1}{4}$Ž cosq = 2, or 4

both are not possible [Q |cosq| £ 1].