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Question: The Q factor of a series LCR circuit with L = 2 H, C= 32\(\mu F\) and R= 10\(\Omega\)is...

The Q factor of a series LCR circuit with L = 2 H, C= 32μF\mu F and R= 10Ω\Omegais

A

15

B

20

C

25

D

30

Answer

25

Explanation

Solution

:Here, ,L=2H,C=32μF=32×106F,L = 2H,C = 32\mu F = 32 \times 10^{- 6}F, R=10ΩR = 10\Omega

\therefore Resonance frequency,

ωr=1LC=12×32×106\omega_{r} = \frac{1}{\sqrt{LC}} = \frac{1}{\sqrt{2 \times 32 \times 10^{- 6}}}

=1038rads1= \frac{10^{3}}{8}rads^{- 1}

Quality factor

=ωrLR=103×28×10=25= \frac{\omega_{r}L}{R} = \frac{10^{3} \times 2}{8 \times 10} = 25