Question

The proposition $p \Rightarrow \sim (p \wedge \sim q)$ is

• A. contradiction
• B. a tautology
• C. either $(a)$ or $(b)$
• D. neither $(a)$ nor $(b)$.

Answer 1

Answer: (D)

neither $(a)$ nor $(b)$.

Answer 2

Result is neither tautology nor contradiction. Hence $(d)$ is correct.