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Question

Mathematics Question on Three Dimensional Geometry

The projections of a directed lines segment on the coordinate axes are 12,4,312, 4, 3 . The direction cosines of the line are

A

1213,413,313\frac{12}{13},\frac{4}{13},\frac{3}{13}

B

1213,413,313\frac{12}{13},\frac{4}{13},-\frac{3}{13}

C

1213,413,313-\frac{12}{13},\frac{4}{13},\frac{3}{13}

D

1213,413,313\frac{12}{13},-\frac{4}{13},-\frac{3}{13}

Answer

1213,413,313\frac{12}{13},\frac{4}{13},\frac{3}{13}

Explanation

Solution

Now, 122+42+32=144+16+9\sqrt{12^2 + 4^2 + 3^2} = \sqrt{144 + 16 + 9}
=169=13= \sqrt{169} = 13
\therefore Required direction cosines are
<1213,413,313>< \frac{12}{13}, \frac{4}{13}, \frac{3}{13} >