Question

The product/s of the reaction, is/are: $Na _{2} CO _{3}+ CO _{2}+ H _{2} O \rightarrow$

• A. $2 NaOH + CO _{2}$
• B. $Na _{2} CO _{3}+ H _{2} CO _{3}$
• C. $2 NaHCO _{3}$
• D. None of these

Answer 1

Answer: (C)

$2 NaHCO _{3}$

Answer 2

When sodium carbonate is treated with $CO _{2}$ and $H _{2} O$, it gets converted into sodium bicarbonate. $Na _{2} CO _{3}+ CO _{2}+ H _{2} O \rightarrow \underset{\text{sodium bicarbonate}}{2 NaHCO _{3}}$