Solveeit Logo

Question

Question: The product of the direction cosines of the line which makes equal angles with \[ox\], \[oy\], \[oz\...

The product of the direction cosines of the line which makes equal angles with oxox, oyoy, ozoz is
A. 1
B. 3\sqrt 3
C. 133\dfrac{1}{{3\sqrt 3 }}
D. 3\sqrt 3

Explanation

Solution

First we will use the formula of direction cosines cos2α+cos2β+cos2γ=1{\cos ^2}\alpha + {\cos ^2}\beta + {\cos ^2}\gamma = 1, where α\alpha is the angle with xx–axis, β\beta is the angle with yy–axis and γ\gamma is the angle with zz–axis. Then we will use that the line makes equal angles with three axis, here α=β=γ\alpha = \beta = \gamma and substitute the obtained value to find the direction cosines. Then we will find the product of the direction cosines of the line.

Complete step by step answer:

We are given that the direction cosines of the line which makes equal angles with oxox, oyoy, ozoz.

We know the formula of direction cosines will be used cos2α+cos2β+cos2γ=1{\cos ^2}\alpha + {\cos ^2}\beta + {\cos ^2}\gamma = 1 , where α\alpha is the angle with xx–axis, β\beta is the angle with yy–axis and γ\gamma is the angle with zz–axis.

Since we are given that the line makes equal angles with three axes, here α=β=γ\alpha = \beta = \gamma .

Thus, we have

cos2α+cos2α+cos2α=1 3cos2α=1  \Rightarrow {\cos ^2}\alpha + {\cos ^2}\alpha + {\cos ^2}\alpha = 1 \\\ \Rightarrow 3{\cos ^2}\alpha = 1 \\\

Dividing the above equation by 3 on both sides, we get

3cos2α3=13 cos2α=13  \Rightarrow \dfrac{{3{{\cos }^2}\alpha }}{3} = \dfrac{1}{3} \\\ \Rightarrow {\cos ^2}\alpha = \dfrac{1}{3} \\\

Taking the square root of the above equation on both sides, we get
cosα=±13\Rightarrow \cos \alpha = \pm \dfrac{1}{{\sqrt 3 }}

Since we know that the above value of direction cosine is the value of all the three direction cosines, so finding the product of the direction cosines of the line from the above equation, we get

(cosα)(cosα)(cosα) ±(13×13×13) ±133  \Rightarrow \left( {\cos \alpha } \right)\left( {\cos \alpha } \right)\left( {\cos \alpha } \right) \\\ \Rightarrow \pm \left( {\dfrac{1}{{\sqrt 3 }} \times \dfrac{1}{{\sqrt 3 }} \times \dfrac{1}{{\sqrt 3 }}} \right) \\\ \Rightarrow \pm \dfrac{1}{{3\sqrt 3 }} \\\

Hence, option C is correct.

Note: In solving these types of questions, students must know that the direction cosines of a line, which are the cosines of the angles made by the line with positive directions of the co-ordinate axes. We can also convert the equation to cosβ\cos \beta or cosγ\cos \gamma , the answer will be same. Students should also avoid calculation mistakes.