Question

The product obtained by treating ${CH_3 - CH = CH_2 + HBr -> ?}$

• A. $\ce{CH_3 - CH_2 - CH_2 Br}$
• B.
• C. $\ce{CH2BrCH = CH2}$
• D. $\ce{CH3 - CH = CHBr}$

Answer 1

Answer: (B)

Answer 2

$CH _{3} CH = CH _{2}+ HBr \longrightarrow CH _{3} CH ( Br ) CH _{3}$ As per Markovnikov's rule, $H$ and Br will be attached as per the compound shown.