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Chemistry Question on Alkenes

The product formed in the following reaction is: CH3CH(CH3)CH=CH2+HBrC{{H}_{3}}CH(C{{H}_{3}})CH=C{{H}_{2}}+HBr →product:\xrightarrow{{}}product:

A

(CH3)2CHCH(Br)CH3{{(C{{H}_{3}})}_{2}}CHCH(Br)C{{H}_{3}}

B

(CH3)2CHCH2CH2Br{{(C{{H}_{3}})}_{2}}CHC{{H}_{2}}C{{H}_{2}}Br

C

(CH3)2C(Br)CH2CH3{{(C{{H}_{3}})}_{2}}C(Br)C{{H}_{2}}C{{H}_{3}}

D

CH3CH(CH3)CH(Br)CH2CH3C{{H}_{3}}CH(C{{H}_{3}})CH(Br)C{{H}_{2}}C{{H}_{3}}

Answer

(CH3)2CHCH(Br)CH3{{(C{{H}_{3}})}_{2}}CHCH(Br)C{{H}_{3}}

Explanation

Solution

The addition of HBr is according to Markownikoff s rule in this reaction. CH3−CH∣ CH3 −CH=CH2+HBr+   − →C{{H}_{3}}-\underset{\begin{smallmatrix} | \\\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-CH=C{{H}_{2}}+\overset{+\,\,\,-}{\mathop{HBr}}\,\xrightarrow{{}} CH3−CH∣ CH3 −CH∣ Br −CH3C{{H}_{3}}-\underset{\begin{smallmatrix} | \\\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-\underset{\begin{smallmatrix} | \\\ Br \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}