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Chemistry Question on trends in periodic table

The process that is NOTNOT endothermic in nature is :-

A

Ar(g)+e−→Ar(g)−Ar _{( g )}+ e ^{-} \rightarrow Ar _{( g ) }^{-}

B

H(g)+e−→H(g)−H _{( g )}+ e ^{-} \rightarrow H _{( g ) }^{-}

C

Na(g)→Nag++e−Na _{( g )} \rightarrow Na _{ g }^{+}+ e ^{-}

D

O(g)−+e−→O(g)2−O _{( g )}^{-}+ e ^{-} \rightarrow O _{ ( g ) }^{2-}

Answer

H(g)+e−→H(g)−H _{( g )}+ e ^{-} \rightarrow H _{( g ) }^{-}

Explanation

Solution

H(g)+e−→H−H _{( g )}+ e ^{-} \rightarrow H ^{-} is exothermic rest of all endothermic process.