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Question: The probability that India wins a cricket test match against England is \(\dfrac{1}{3}\) . If India ...

The probability that India wins a cricket test match against England is 13\dfrac{1}{3} . If India and england plays 3 matches, the probability that India will win at least one match is
A) 827\dfrac{8}{{27}}
B) 1927\dfrac{{19}}{{27}}
C) 127\dfrac{1}{{27}}
D) 927\dfrac{9}{{27}}

Explanation

Solution

Hint: Try to find the total probability that india will not win any test match then use that probability to find that india will win at least 1 match by subtracting it from 1.
Complete step by step answer:
It is given that the probability that india will win no game at all will be given by
113=313=231 - \dfrac{1}{3} = \dfrac{{3 - 1}}{3} = \dfrac{2}{3}
P(LossIndia)=23\therefore P(Los{s_{India}}) = \dfrac{2}{3}
It is given that 3 consecutive games are played therefore the probability that india will lose all of them will be P(LossIndia)=23×23×23=827\therefore P(Los{s_{India}}) = \dfrac{2}{3} \times \dfrac{2}{3} \times \dfrac{2}{3} = \dfrac{8}{{27}}
Now for getting the required result that India won at least 1 match will be given by
P(WinIndia)=1827=27827=1927P(Wi{n_{India}}) = 1 - \dfrac{8}{{27}} = \dfrac{{27 - 8}}{{27}} = \dfrac{{19}}{{27}}
So our required answer is 1927\dfrac{{19}}{{27}}
Therefore, option B is the correct answer.

Note: The highest probability can only be 1 if in any case you get a probability that is greater than 1 that means you made a mistake somewhere and also we can use this 1 to get a complement of probability we need.