Question

The probability that an ordinary or a non-leap year has 53 sunday, is

• A. $\frac { 2 } { 7 }$
• B. $\frac { 1 } { 7 }$
• C. $\frac { 3 } { 7 }$
• D. None of these

Answer 1

Answer: (B)

$\frac { 1 } { 7 }$

Answer 2

In a non-leap year, we have 365 days i.e., 52 weeks and one day. So, we may have any day of seven days. Therefore, 53 Sunday, required probability = $\frac { 1 } { 7 }$ .