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Question: The probability that *A* speaks truth is \(\frac { 4 } { 5 }\) , while this probability for *B* is...

The probability that A speaks truth is 45\frac { 4 } { 5 } , while this

probability for B is 34\frac { 3 } { 4 } . The probability that they contradict

each other when asked to speak on a fact is

A

45\frac { 4 } { 5 }

B

15\frac { 1 } { 5 }

C

720\frac { 7 } { 20 }

D

320\frac { 3 } { 20 }

Answer

720\frac { 7 } { 20 }

Explanation

Solution

Let E be the event that B speaks truth and F be the event that A speaks truth.

Now P(E)=75100=34P ( E ) = \frac { 75 } { 100 } = \frac { 3 } { 4 } and P(F)=80100=45P ( F ) = \frac { 80 } { 100 } = \frac { 4 } { 5 }.

∴ P (A and B contradict each other)

= P [(B tells truth and A tells lie) or (B tells lie and A tells truth)]

.