The probability that a leap year will have 53 Fridays or 53... | MATH - USE OF PERMUTATIONS AND COMBINATIONS IN PROBABILITY | SolveeIt | Solveeit

Today, August 18

Question

The probability that a leap year will have 53 Fridays or 53 Saturdays is -

A

$\frac { 2 } { 7 }$

B

$\frac { 3 } { 7 }$

C

$\frac { 4 } { 7 }$

D

$\frac { 1 } { 7 }$

Answer

$\frac { 3 } { 7 }$

Explanation

Solution

S = {(Sun, Mon), (Mon, Tue), (Tue, Wed), (Wed, Thurs), (Thurs, Fri) (Fri, Sat) (Sat, Sun)}

P (53 Fridays or 53 Saturdays) = $\frac { 3 } { 7 }$