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Question: The probability that A, B, C solve a problem is ½, 2/3 and ¾. The probability that the problem is so...

The probability that A, B, C solve a problem is ½, 2/3 and ¾. The probability that the problem is solved by only one of them is

A

5/12

B

¼

C

7/24

D

19/24

Answer

¼

Explanation

Solution

Required probability

= P (ABC)+P(ABC)+P(ABC)( \overline { \mathrm { A } } \cap \overline { \mathrm { B } } \cap \overline { \mathrm { C } } ) + \mathrm { P } ( \overline { \mathrm { A } } \cap \mathrm { B } \cap \overline { \mathrm { C } } ) + \mathrm { P } ( \overline { \mathrm { A } } \cap \overline { \mathrm { B } } \cap \mathrm { C } )

= P(1) P(A\overline { \mathrm { A } }) P(2) P( C\overline { \mathrm { C } } ) +

=12×13×14+12×23×14+12×13×34=624\frac { 1 } { 2 } \times \frac { 1 } { 3 } \times \frac { 1 } { 4 } + \frac { 1 } { 2 } \times \frac { 2 } { 3 } \times \frac { 1 } { 4 } + \frac { 1 } { 2 } \times \frac { 1 } { 3 } \times \frac { 3 } { 4 } = \frac { 6 } { 24 }