Question

The probability of hitting a target by three marksmen are $\frac { 1 } { 2 } , \frac { 1 } { 3 }$ and $\frac { 1 } { 4 }$ respectively. The probability that one and only one of them will hit the target when they fire simultaneously, is

• A. $\frac { 11 } { 24 }$
• B. $\frac { 1 } { 12 }$
• C. $\frac { 1 } { 8 }$
• D. None of these

Answer 1

Answer: (A)

$\frac { 11 } { 24 }$

Answer 2

Here $P ( A ) = \frac { 1 } { 2 }$ $P ( B ) = \frac { 1 } { 3 }$ $P ( C ) = \frac { 1 } { 4 }$

Hence required probability