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Question: The probability of happening an event *A* is 0.5 and that of *B* is 0.3. If *A* and *B* are mutuall...

The probability of happening an event A is 0.5 and that of B is

0.3. If A and B are mutually exclusive events, then the

probability of happening neither A nor B is

A

0.6

B

0.2

C

0.21

D

None of these

Answer

0.2

Explanation

Solution

P(Aˉ∩Bˉ)=P(A∪B‾)=1−P(A∪B)P ( \bar { A } \cap \bar { B } ) = P ( \overline { A \cup B } ) = 1 - P ( A \cup B ) Since A and B are

mutually exclusive, so P(A∪B)=P(A)+P(B)P ( A \cup B ) = P ( A ) + P ( B ) Hence, required

probability=1−(0.5+0.3)=0.2= 1 - ( 0.5 + 0.3 ) = 0.2.