Question

The probability of getting even number, when a die is thrown once, is
A. $\dfrac{1}{2}$
B. $\dfrac{1}{3}$
C. $\dfrac{1}{6}$
D. $\dfrac{5}{6}$

Answer 1

As the question says that here we have to find the probability of getting an even number when die is thrown, so first we have to assume that die has six sides and all the outcome equally likely that means let the die is fairly die.

Complete step-by-step answer:
The sample die has six possible outcome that is 1, 2, 3, 4, 5 and 6
And all the outcome has fairly outcome
So, the probability of any outcome is $\dfrac{1}{6}$
The possibility of getting even number on tossing the die can occur in 3 possible ways
We have even number in the sample die outcome is 2, 4 and 6
We can denote this event by A = {2,4,6}
Total even number outcome is 3
The probability of getting even number when a die is thrown is
Total even number outcome divided by total number of outcomes
$P(A) = \dfrac{3}{6}$
$P(A) = \dfrac{1}{2}$
The probability of getting even number outcome when a die is thrown is $\dfrac{1}{2}$

So, the correct answer is “Option A”.

Note: Students can solve this question by an alternative method that is discrete uniform law this means we can find the probability of even numbers outcome by just counting the even numbers in total outcomes. P{A} = $\dfrac{k}{n}$ where k is the number of elements and n is the total number of outcomes.
In this question we have 3 even numbers and the total number is 6 so, we have P{A} =$\dfrac{3}{6}$ that is $\dfrac{1}{2}$.