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Question

Physics Question on Bernauli Theorem

The probability of getting at least 2 heads, when an unbiased coin is tossed 6 times is

A

6364\frac{63}{64}

B

5764\frac{57}{64}

C

764\frac{7}{64}

D

3764\frac{37}{64}

Answer

5764\frac{57}{64}

Explanation

Solution

P(E)=26−1−626=64−764=5764P(E) = \frac{2^6 - 1 - 6}{2^6} = \frac{64 -7}{64} = \frac{57}{64}