Question

The probability of getting a total of 5 or 6 in a single throw of 2 dice is

• A. $\frac { 1 } { 2 }$
• B. $\frac { 1 } { 4 }$
• C. $\frac { 1 } { 3 }$
• D. $\frac { 1 } { 6 }$

Answer 1

Answer: (B)

$\frac { 1 } { 4 }$

Answer 2

Total number of ways $= 36$

Favourable numbers of cases are $( 14 ) , ( 2,3 ) , ( 3,2 )$ $( 4,1 ) , ( 1,5 ) , ( 2,4 ) , ( 3,3 ) , ( 4,2 ) , ( 5,1 ) = 9$

Hence the required probability $= \frac { 9 } { 36 } = \frac { 1 } { 4 }$