Question

The probability of getting a sum of 8, when two dice are thrown simultaneously, is :

• A. $\frac{1}{12}$
• B. $\frac{1}{9}$
• C. $\frac{1}{6}$
• D. $\frac{5}{36}$

Answer 1

Answer: (D)

$\frac{5}{36}$

Answer 2

The possible pairs that result in a sum of 8 are:
$(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)$
There are 5 such outcomes. Total outcomes when two dice are thrown is $6 \times 6 = 36$. Therefore, the probability is:
$P = \frac{5}{36}$