Question

The probability of a number ‘n’ showing in a throw of a dice marked 1 to 6 is proportional to n, then probability of number ‘3’ showing in a throw is :

• A. $\frac { 1 } { 2 }$
• B. $\frac { 1 } { 6 }$
• C. $\frac { 1 } { 7 }$
• D. None

Answer 1

Answer: (C)

$\frac { 1 } { 7 }$

Answer 2

$\frac { 6.7 } { 2 }$= 1

Ž k = $\frac { 1 } { 21 }$

Now P(3) = 3k = $\frac { 3 } { 21 }$ = $\frac { 1 } { 7 }$