Question

The probability distribution curve for 2s electron appears like–

• A.
• B.
• C.
• D.

Answer 1

Answer: (A)

Answer 2

Y_2s = $\frac{1}{4\sqrt{2\pi}}$ × $\left( \frac{1}{a_{0}} \right)^{3/2}$× $\left( 2 - \frac{r}{a_{0}} \right)e^{- r/a_{0}}$

$\psi_{2s}^{2}$= K$\left( 2 - \frac{r}{a_{0}} \right)^{2}e^{- 2r/a_{0}}$