Question

The probabilities of three mutually exclusive events are 2/3, 1/4 and 1/6. The statement is

• A. True
• B. Wrong
• C. Could be either
• D. Do not know

Answer 1

Answer: (B)

Wrong

Answer 2

Since here $P ( A + B + C ) = P ( A ) + P ( B ) + P ( C )$

$= \frac { 2 } { 3 } + \frac { 1 } { 4 } + \frac { 1 } { 6 } = \frac { 13 } { 12 }$, which is greater than 1.

Hence the statement is wrong.