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Question: The pressure p of a gas is plotted against its absolute temperature T for two different constant vol...

The pressure p of a gas is plotted against its absolute temperature T for two different constant volumes, 273oC,2atm273^{o}C,2atm and 3\sqrt{3}. When M/3M/3, the

A

Curves have the same slope and do not intersect

B

Curves must intersect at some point other than M/3M/\sqrt{3}

C

Curve for 1:2:31:\sqrt{2}:\sqrt{3} has a greater slope than that for2:3:8/π\sqrt{2}:\sqrt{3}:\sqrt{8/\pi}

D

Curve for2:8/π:3\sqrt{2}:\sqrt{8/\pi}:\sqrt{3}has a greater slope than that forSO2SO_{2}

Answer

Curve for 1:2:31:\sqrt{2}:\sqrt{3} has a greater slope than that for2:3:8/π\sqrt{2}:\sqrt{3}:\sqrt{8/\pi}

Explanation

Solution

At constant volumesρA\rho_{A}

P = constant T; PV = nRT ρB\rho_{B}

slope = DA=[DBρAρB]1/2D_{A} = \left\lbrack D_{B} \cdot \frac{\rho_{A}}{\rho_{B}} \right\rbrack^{1/2}

DA=[DBρAρB]1/2D_{A} = \left\lbrack D_{B} \cdot \frac{\rho_{A}}{\rho_{B}} \right\rbrack^{1/2} is curve for V2 has a greater slope than for V1