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Question: The pressure on a swimmer 20 m below the surface of water at sea level is (Take, atmospheric pressur...

The pressure on a swimmer 20 m below the surface of water at sea level is (Take, atmospheric pressure =1×105= 1 \times 10 ^ { 5 }Pa)

A

(a) 1.0 atm

A

(b) 2.0 atm

A

(c) 2.5 atm

A

(d) 3.0 atm

Explanation

Solution

(d) Here, h = 20 m

Density of water ρ=103 kg m−3\rho = 10 ^ { 3 } \mathrm {~kg} \mathrm {~m} ^ { - 3 }

Atmospheric pressure

=1×105+103×10×20= 1 \times 10 ^ { 5 } + 10 ^ { 3 } \times 10 \times 20

=1×105+2×105= 1 \times 10 ^ { 5 } + 2 \times 10 ^ { 5 }

=3×105 Pa=3 atm= 3 \times 10 ^ { 5 } \mathrm {~Pa} = 3 \mathrm {~atm}