Question

The pressure of a moist gas at 27°C is 4 atm. The volume of the container is doubled at the same temperature. The new pressure of the moist gas is ______ ×10–1 atm. (Nearest integer)(Given: The vapor pressure of water at 27°C is 0.4 atm.)

Answer 1

From ideal gas equation,|
P∝$\frac{1}{v}$
P1V1 = P2V2
Pressure of the gas = 4 – 0.4 = 3.6 atm
3.6 V1 = P2 (2V1)
P2 = 1.8 atm
Hence, new pressure of moist gas is
1.8 + 0.4 = 2.2 atm = 22 × 10–1atm