Question

The pressure of a mixtures of equal weights of two gases X and Y with molecular weight 4 and 40 respectively is $1.1$atm. The partial pressure of the gas X in the mixture is.

• A. 1 atm
• B. $0.1$atm
• C. $0.15$atm
• D. $0.5$atm

Answer 1

Answer: (A)

1 atm

Answer 2

: Let w g of each gas is taken.

Mole fraction of $X = \frac{\frac{w}{4}}{\frac{w}{4} + \frac{w}{40}} = \frac{10}{11}$

Partial pressure of

X = $P_{total} \times Molefraction$

$= 1.1 \times \frac{10}{11} = 1atm$