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Question: The pressure of a gas filled in the bulb of a constant volume gas thermometer at \(0^{\circ}C\) and ...

The pressure of a gas filled in the bulb of a constant volume gas thermometer at 0C0^{\circ}C and 100C100^{\circ}C are 28.6cm28.6cmand 36.6cm36.6cm of mercury respectively. The temperature of bulb at which pressure will be 35cm35cmof mercury will be:

& A{{.80}^{\circ }}C \\\ & B{{.70}^{\circ }}C \\\ & C{{.55}^{\circ }}C \\\ & D{{.40}^{\circ }}C \\\ \end{aligned}$$
Explanation

Solution

A thermometer is an instrument which is used to measure the heat of any given body. It works on the principle of the zeroth law of thermodynamics. The zeroth law of thermodynamics states that, if two systems AA and BB are in thermal equilibrium with a third system CC then, the system AA and BB are said to be in thermal equilibrium with each other.

Formula used:
TT1T2T1=PP1P2P1\dfrac{T-T_{1}}{T_{2}-T_{1}}=\dfrac{P-P_{1}}{P_{2}-P_{1}}

Complete answer:
We know that a constant volume gas thermometer is a thermometer whose bulb contains some fixed amount of dilute mercury. Mercury is used in the thermometer because of its high coefficient of expansion and it is one of the liquids which is in liquid state at room temperature.
From Gay-Lussac’s law of gases, we know that at constant volume, the pressure of an ideal gas is directly proportional to the temperature at which the pressure is measured.
Let us assume that the mercury gas in the thermometer is ideal in nature. Then from Gay-Lussac’s law of gases, PTP\propto T, then we can also say that ΔPΔT\Delta P\propto \Delta T
Here it is given that, P1=28.6cmP_{1}=28.6cm at T1=0CT_{1}=0^{\circ}C and P2=36.6P_{2}=36.6 at T2=100CT_{2}=100^{\circ}C.
Let P=35cmP=35cm at TT
Let us take the T1=0T_{1}=0^{\circ} as the reference, then we can say that TT1PP1T-T_{1}\propto P-P_{1} similarly, T2T1P2P1T_{2}-T_{1}\propto P_{2}-P_{1}
Taking the ratio we get TT1T2T1=PP1P2P1\dfrac{T-T_{1}}{T_{2}-T_{1}}=\dfrac{P-P_{1}}{P_{2}-P_{1}}
Substituting we get, T01000=3528.636.628.6\dfrac{T-0}{100-0}=\dfrac{35-28.6}{36.6-28.6}
On solving we get, T=3528.636.628.6×100C=6.48×100C=0.8×100C=80CT=\dfrac{35-28.6}{36.6-28.6}\times 100^{\circ}C=\dfrac{6.4}{8}\times 100^{\circ}C=0.8\times 100^{\circ}C=80^{\circ}C

So, the correct answer is “Option A”.

Note: The constant volume mercury thermometer is the normal thermometer which is used by doctors to measure the body temperature of a patient. However, the same is used for experiments also, but the scale of the thermometer may vary depending on the need of the experiment