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Question

Chemistry Question on Partial pressure

The pressure o f a 1:41 : 4 mixture of dihydrogen and dioxygen enclosed in a vessel is one atmosphere. What would be the partial pressure of dioxygen?

A

0.8×1050.8 \times 10^{5} atm

B

0.008 N m−20.008 \, N\, m^{-2}

C

8×104Nm−28 \times 10^{4} N m^{-2}

D

0.250.25 atm

Answer

8×104Nm−28 \times 10^{4} N m^{-2}

Explanation

Solution

pO2=xO2×Ptotalp_{O_{2}}=x_{O_2}\times P_{total} Given : Ptotal=1P_{total}=1 atm, xO2=45x_{O_2}=\frac{4}{5} pO2=45×1=0.8p_{O_2}=\frac{4}{5}\times1=0.8 atm (∵\because 1 atm =1.01325×105pa=1.01325\times10^{5}pa or N m−2N\,m^{-2}) =0.8×105 N m−2=0.8\times10^{5}\,N \,m^{-2} =8×104N m−2=8\times10^{4} N\,m^{-2}