Question

The pressure inside two soap bubbles are 1.02 atm. and 1.03 atm. respectively. The ratio of their volumes is –

• A. 102 : 103
• B. 103 : 102
• C. (103)³ : (102)³
• D. 27 : 8

Answer 1

Answer: (D)

27 : 8

Answer 2

P_in – P_atm = excess pressure = $\frac{4T}{R}$

\ $\frac{R_{1}}{R_{2}}$ = $\frac{\Delta P_{2}}{\Delta P_{1}}$= $\frac{3}{2}$

\ $\frac{V_{1}}{V_{2}}$= $\frac{{R_{1}}^{3}}{{R_{2}}^{3}}$ = $\frac{27}{8}$