Question

The pressure inside a small air bubble of radius 0.1mm situated just below the surface of water will be equal to(Take surface tension of water $70 \times 10^{- 3}Nm^{- 1}$ and atmospheric pressure $= 1.013 \times 10^{5}Nm^{- 2}$)

• A. $2.054 \times 10^{3}Pa$
• B. $1.027 \times 10^{3}Pa$
• C. $1.027 \times 10^{5}Pa$
• D. $2.054 \times 10^{5}Pa$

Answer 1

Answer: (C)

$1.027 \times 10^{5}Pa$

Answer 2

Pressure inside a bubble when it is in a liquid $= P_{o} + \frac{2T}{R} = 1.013 \times 10^{5} + 2 \times \frac{70 \times 10^{- 3}}{0.1 \times 10^{- 3}} = 1.027 \times 10^{5}$Pa