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Question

Physics Question on Pressure

The pressure exerted by 55 moles of a real gas in one litre vessel at 47??47^?? is (a=3.592atmL2mol2(a = 3.592 \,atm\, L^2\, mol^{-2}, b=0.0427Lmol1)b = 0.0427\, L\, mol^{-1})

A

149atm149\, atm

B

77.2atm77.2\, atm

C

47.4atm47.4\, atm

D

18.4atm18.4\, atm

Answer

77.2atm77.2\, atm

Explanation

Solution

Applying, (P+an2V2)(Vnb)=nRT\left(P+\frac{an^{2}}{V^{2}}\right)\left(V-nb\right)=nRT a=3.592a=3.592, b=0.0427b=0.0427, V=1LV=1\,L, n=5moln=5\,mol, T=273+47=320KT=273+47=320\,K R=0.0821LatmK1mol1R=0.0821\,L\,atm\,K^{-1}\,mol^{-1} (P+3.592×5212)(15×0.0427)\left(P+\frac{3.592\times5^{2}}{1^{2}}\right)\left(1-5\times0.0427\right) =5×0.0821×320=5\times0.0821\times320 P=77.2atmP=77.2\,atm