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Question: The pressure and temperature of \(PV = nRT\) of carbon dioxide gas are doubled. Then the volume of c...

The pressure and temperature of PV=nRTPV = nRT of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would be.

A

8.31×107ergK−1mol−18.31 \times 10^{7}ergK^{- 1}mol^{- 1}

B

8.31×107dynecmK−1mol−18.31 \times 10^{7}dynecmK^{- 1}mol^{- 1}

C

8.31JK−1mol−18.31JK^{- 1}mol^{- 1}

D

8.31atm.K−1mol−18.31atm.K^{- 1}mol^{- 1}

Answer

8.31JK−1mol−18.31JK^{- 1}mol^{- 1}

Explanation

Solution

PV=nRTPV = nRT; PV=nRT\mathbf{PV = nRT}

8.31×1078.31 \times 10^{7} so K−1K^{- 1}