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Question

Physics Question on Resistance

The practical unit of resistance is Ω.1Ω\Omega .1 \, \Omega is equal to:

A

101810^{18} emu

B

10910^9 emu

C

101510^{15} emu

D

none of these

Answer

10910^9 emu

Explanation

Solution

From Ohm's law we have, V=IRV =I R R=VI\Rightarrow R =\frac{V}{I} where, RR is resistance, VV is voltage and II is current. Also unit of voltage is 10810^{8} emu of potential and unit of current is 110\frac{1}{10} emu of current. R=108emu of potential 110emu of current \therefore R =\frac{10^{8} \text{emu of potential }}{\frac{1}{10} \text{emu of current }} =109=10^{9} emu of resistance