Question

The power output of an automobile engine is advertised to be 200 hp at 600 rpm. Find the corresponding torque

• A. 137 Nm
• B. 237 Nm
• C. 337 Nm
• D. 287Nm

Answer 1

Answer: (B)

237 Nm

Answer 2

τ = $\frac{P}{\omega} = \frac{200 \times 746}{600 \times \frac{2\pi}{60}} = 237N - m$.