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Question

Question: The power factor of the circuit as shown in figure is <img src="https://cdn.pureessence.tech/canvas...

The power factor of the circuit as shown in figure is

A

0.2

B

0.4

C

0.8

D

0.6

Answer

0.8

Explanation

Solution

: Resistance of circuit,

R=R1+R2=40Ω+40Ω=80Ω\mathrm { R } = \mathrm { R } _ { 1 } + \mathrm { R } _ { 2 } = 40 \Omega + 40 \Omega = 80 \Omega

Impedance of the circuit,

Z=R2+(XLXC)2=(80)2+(10040)2\mathrm { Z } = \sqrt { \mathrm { R } ^ { 2 } + \left( \mathrm { X } _ { \mathrm { L } } - \mathrm { X } _ { \mathrm { C } } \right) ^ { 2 } } = \sqrt { ( 80 ) ^ { 2 } + ( 100 - 40 ) ^ { 2 } }

=(80)2+(60)2=100Ω= \sqrt { ( 80 ) ^ { 2 } + ( 60 ) ^ { 2 } } = 100 \Omega

Power factor,