Solveeit Logo

Question

Physics Question on LCR Circuit

The power factor of R-L circuit is 13\frac{1}{\sqrt{3}}. If the inductive reactance is 2Ω2\Omega. The value of resistance is

A

2Ω2\Omega

B

2Ω\sqrt{2}\Omega

C

0.5Ω0.5\Omega

D

12Ω\frac{1}{\sqrt{2}}\Omega

Answer

2Ω\sqrt{2}\Omega

Explanation

Solution

cosϕ=13,tanϕ=21tanϕ\cos \phi=\frac{1}{\sqrt{3}}, \tan \phi=\frac{\sqrt{2}}{1} \tan \phi
=XLR2=2R=\frac{X_{L}}{R} \sqrt{2}=\frac{2}{R}
R=2Ω\Rightarrow R=\sqrt{2} \Omega