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Question

Physics Question on Electric Power

The power dissipated in 3Ω3 \Omega resistance in the following circuit is

A

0.75 W

B

0.25 W

C

1 W

D

0.5 W

Answer

0.75 W

Explanation

Solution

The equivalent circuit of the given circuit will be

From circuit, 1R=13+16\frac{1}{R} =\frac{1}{3}+\frac{1}{6}
=2+16=36Ω=\frac{2+1}{6}=\frac{3}{6} \,\Omega
R1=2ΩR_1=2\,\Omega
R2=R2+R2+R4R_{2} =R_{2}+R_{2}+R_{4}
=2+2+4=8Ω=2+2+4=8 \,\Omega
The internal resistance of battery =1Ω=1 \,\Omega
So, the equivalent resistance of circuit
=8Ω+1Ω=8 \Omega+1 \Omega
=9Ω=9 \,\Omega
The current in the circuit
I=VR=459I=\frac{V}{R}=\frac{45}{9}
=12A=\frac{1}{2} A
The power dissipated in 3Ω3 \Omega resistance
P=I2×RP =I^{2} \times R
=(12)2×3=\left(\frac{1}{2}\right)^{2} \times 3
=14×3=\frac{1}{4} \times 3
=0.75W=0.75 \,W