Question
Physics Question on electrostatic potential and capacitance
The potential of the electric field produced by a point charge at any point (x,y,z) is given by V=3x2+5 , where x,y,z are in metres and V is in volts. The intensity of the electric field at (−2,1,0) is
A
+17Vm−1
B
−17Vm−1
C
+12vm−1
D
−12Vm−1
Answer
+12vm−1
Explanation
Solution
Potential (V)=3x2+5
Intensity of the electric field, E=dx−dV
∴E=−dxd(3x2+5)=−6x
∴E∣x=−2=−6(−2)=12V/m