Question

The potential of the Daniell cell,$Zn\left| \underset{(1M)}{ZnSO_{4}} \right|\left| \underset{(1M)}{CuSO_{4}} \right|Cu$ was reported by Buckbee, Surdzial and Metz as E⁰ = 1.1028 – 0.641 × 10–3 T + 0.72 × 10–5 T2, where T is the temperature in degree celsius. Calculate $\Delta S^{0}$ for the cell reaction at 25⁰C

• A. – 45.32 EU
• B. – 34.52 EU
• C. – 25.43 EU
• D. – 54.23 EU

Answer 1

Answer: (D)

– 54.23 EU

Answer 2

E⁰ = 1.1028 – 0.641 × 10–3 T + 0.72 × 10–5 T2

}{( - 0641 + 0.36) \times 10^{- 3} = - 0.281 \times 10^{- 3}}$$ $$\Delta\text{ }\text{S}^{0}\text{ = nF }\frac{dE^{0}}{dT}\text{= 2 }\text{×}\text{ 96500 }\text{×}\text{ }(\text{-281 }\text{×}\text{ 1}\text{0}^{\text{-3}})\text{ = - 54.23 EU}$$