Question
Question: The potential of hydrogen electrode at \[25^\circ {\text{C}}\] will be: \[({{\text{P}}_{{{\text{H}}_...
The potential of hydrogen electrode at 25∘C will be: (PH2=1 atm, concentration of H+ = 0.1M)
A.) 0.00 V
B.) -0.059 V
C.) 0.118 V
D.) 0.059 V
Solution
We know that Nernst equation is used to get the value of electrode potential. It relates, cell potential, temperature, reaction quotient and standard cell potential to each other.
Complete step by step answer:
We have been given the temperature to be 25∘C i.e. 25∘C + 273 = 298K. Also, PH2=1 atmand [H+] = 0.1M.
Reaction occurring on hydrogen electrode is –
2H+ + 2e− → H2.
At 25∘C, Nernst equation is given as - Ecell = E0 - 20.059log[H+]PH2
Substituting given values in above equation we get,
Ecell = 0 - 0.059 log(0.1)1
(standard electrode potential of hydrogen electrode is taken as 0. Hence, E0 = 0.)