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Question

Physical Chemistry Question on Atomic Structure

The potential for a particle in a one-dimensional box is given as:
V(x)=0V(x)=0 for 0xL,0≤x≤L, and V(x)=V(x) = ∞ elsewhere.
The locations of the internal nodes of the eigenfunctions Ψn(x),n2\Psi _n(x), n≥2, are
[Given: m is an integer such that 0<m<n]

A

x=m+12nLx=\frac{m+\frac1{2}}{n}L

B

x=mnLx=\frac{m}{n} L

C

x=mn+1Lx=\frac{m}{n+1} L

D

x=m+1n+1Lx=\frac{m+1}{n+1} L

Answer

x=mnLx=\frac{m}{n} L

Explanation

Solution

The correct option is (B): x=mnLx=\frac{m}{n} L