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Question: The potential energy U for a force field ![](https://cdn.pureessence.tech/canvas_389.png?top_left_x=...

The potential energy U for a force field is such that U = – Kxy, where K is a constant –

A

F=Kyi^+Kxj^\overrightarrow { \mathrm { F } } = K y \hat { i } + K x \hat { j }

B

F=Kxi^+Kyj^\vec { F } = K x \hat { i } + K y \hat { j }

C

F=Kyi^Kxj^\overrightarrow { \mathrm { F } } = K y \hat { \mathrm { i } } - K x \hat { j }

D

F=Kxi^Kyj^\vec { F } = K x \hat { i } - K y \hat { j }

Answer

F=Kyi^+Kxj^\overrightarrow { \mathrm { F } } = K y \hat { i } + K x \hat { j }

Explanation

Solution

F=U\overrightarrow { \mathrm { F } } = - \vec { \nabla } \mathrm { U } = K()