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Question

Physics Question on potential energy

The potential energy of a spring when stretched through a distance xx is 10J10\, J. What is the amount of work done on the same spring to stretch it through an additional distance xx ?

A

10J10\, J

B

20J20\, J

C

30J30\, J

D

40J40\, J

Answer

30J30\, J

Explanation

Solution

Potential energy of the spring when stretched through a distance xx, U=12kx2=10JU = \frac{1}{2}kx^{2} = 10\,J When xx becomes 2x2x, the potential energy will be U=12k(2x)2=4×12kx2U' = \frac{1}{2}k\left(2x\right)^{2}= 4 \times \frac{1}{2}kx^{2} =4×10=40J= 4 \times 10 = 40\,J \therefore Work done =UU=4010=30J= U' - U = 4 0 - 10 = 30 \,J