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Question

Question: The potential energy of a particle varies with distance x from a fixed origin as \(U = \frac{A\sqrt{...

The potential energy of a particle varies with distance x from a fixed origin as U=Axx+BU = \frac{A\sqrt{x}}{x + B} where A and B are constants. The dimensions of AB are –

A

ML5/2 T–2

B

1L2T–2

C

M3/2 L5/2 T–2

D

M1L7/2T–2

Answer

M1L7/2T–2

Explanation

Solution

ML2T–2 = [A]L1/2L\frac{\lbrack A\rbrack L^{1/2}}{L}

[A] = ML5/2T–2

[B] = L