Question
Question: The potential energy of a particle varies with distance x from a fixed origin as \(U = \frac{A\sqrt{...
The potential energy of a particle varies with distance x from a fixed origin as U=x+BAx where A and B are constants. The dimensions of AB are –
A
ML5/2 T–2
B
1L2T–2
C
M3/2 L5/2 T–2
D
M1L7/2T–2
Answer
M1L7/2T–2
Explanation
Solution
ML2T–2 = L[A]L1/2
[A] = ML5/2T–2
[B] = L