Question

The potential energy of a particle of mass 5 kg moving in x-y plane is given by U = (–7x + 24y) J, where x and y are in meters. If particle starts from rest from origin, then speed of particle at t = 2 sec, is –

• A. 5 m/s
• B. 10 m/s
• C. 14 m/s
• D. 17.5 m/s

Answer 1

Answer: (B)

10 m/s

Answer 2

$\vec { \nabla }$.U = (7– 24) ̃ a == 5 m/s²

Hence v = at = 10 m/s