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Question: The potential energy of a particle having mass \(m\) is given by \(U = \dfrac{1}{2}k{x^2}\) for \(x ...

The potential energy of a particle having mass mm is given by U=12kx2U = \dfrac{1}{2}k{x^2} for x<0x < 0 and U=0U = 0 for x0x \geqslant 0. If the total mechanical energy of the particle is EE, then its speed at x=2Ekx = \sqrt {\dfrac{{2E}}{k}} is
(A) Zero
(B) 2Em\sqrt {\dfrac{{2E}}{m}}
(C) 2Em\sqrt {\dfrac{{2E}}{m}}
(D) E2m\sqrt {\dfrac{E}{{2m}}}

Explanation

Solution

Hint Here, write the potential energy and substitute the value of distance at which speed is to be determined. Then, substitute the value of energy to the mechanical energy expression to find kinetic energy and then in the expression of kinetic energy to find the speed.
Formula Used: Here we will be using the formula for conservation of mechanical energy is E=U+KE = U + K, where EE is the mechanical energy, UU is the potential energy and KK is the kinetic energy.

Complete step by step solution
The given potential energy of a particle of mass mm for x<0x < 0 is U=12kx2U = \dfrac{1}{2}k{x^2}, here, the distance travelled in xx axis and the potential energy for x0x \geqslant 0 is U=0U = 0.
The total mechanical energy of the particle is EE.
The value of distance at which speed is to be determined is,
x=2Ek\Rightarrow x = \sqrt {\dfrac{{2E}}{k}}
Substitute 2Ek\sqrt {\dfrac{{2E}}{k}} for xx in the expression of potential energy for x<0x < 0.
U=12k(2Ek)2\Rightarrow U = \dfrac{1}{2}k{\left( {\sqrt {\dfrac{{2E}}{k}} } \right)^2}
Reduce the above equation.
U=12k×2Ek\Rightarrow U = \dfrac{1}{2}k \times \dfrac{{2E}}{k}
Cancel out the same terms in division.
U=E\Rightarrow U = E
According to conservation of energy, mechanical energy is expressed as:
E=U+KE = U + K
From the above, substitute EE for UU in the above expression.
E=E+KE = E + K
Take the same variable to one side to determine the value of kinetic energy and rearrange the expression.
K=EE=0K = E - E = 0
Formula for kinetic energy is given by
K=12mv2K = \dfrac{1}{2}m{v^2}
Here, mm is the mass and vv is the velocity or speed measured in meters per second.
Substitute 00 for KK in the above expression.
0=12mv2\Rightarrow 0 = \dfrac{1}{2}m{v^2}
v=0\Rightarrow v = 0

So, option (B) is correct answer

Additional information Energy possessed by an object due to its motion or position is defined as the mechanical energy. According to physical science mechanical energy is also defined as the sum of kinetic energy and potential energy.

Note Principle of conservation of mechanical energy is known to solve the questions. Also, for stationary position kinetic energy equals to zero. Thus, kinetic energy is to be only determined when the object is in moving condition.