The potential energy of a particle (4(U\_x)) executing SHM i... | Physics | SolveeIt

The potential energy of a particle $4(U_x)$ executing SHM is given by

$U_x=\frac{K}{2}(x-a)^2$

$U_x=K_1x+K_2x^2+K_3x^3$

$U_x=Ae^{-bx}$

$U_x=constant$

Answer

$U_x=\frac{K}{2}(x-a)^2$

Explanation

Answer (a) $U_x=\frac{K}{2}(x-a)^2$

Physics Question on potential energy