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Question

Physics Question on work, energy and power

The potential energy of a long spring when stretched by 2 cm is U. If the spring is stretched by 8 cm the potential energy stored in it is:

A

4U

B

U8\frac U8

C

16U

D

U4\frac U4

Answer

16U

Explanation

Solution

U=12K(2)2=2KU = \frac 12K(2)^2 = 2K

U=12K(8)2=32KU' = \frac 12K(8)^2 = 32K

Now,

UU=32K2K\frac {U'}{U} = \frac {32K}{2K}

UU=16\frac {U'}{U} = 16

U=16UU' = 16U

So, the correct option is (C): 16U