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Question

Physics Question on potential energy

The potential energy of a conservative system is given by V(x)=(x23x)V(x) = (x^2 - 3x) joule. Then its equilibrium position is at

A

x=1.5mx = 1.5\, m

B

x=2mx = 2 \,m

C

x=2.5mx = 2.5 \,m

D

x=3mx = 3 \,m

Answer

x=1.5mx = 1.5\, m

Explanation

Solution

Given, V(x)=(x23x)V ( x )=\left( x ^{2}-3 x \right)
For condition of equilibrium, dV(x)dx=0\frac{ dV ( x )}{ dx }=0
Hence, dV(x)dx=2x3\frac{ dV ( x )}{ dx }=2 x -3
So, 2x3=02 x -3=0
x=1.5m x =1.5 m